6th Puzzle Answer

If we make ß = Pi/2 (+/- 2k Pi) radians and R = 1, then the
second formula is equal to i.

Therefore i = e^{i(Pi/2 +/- 2k Pi)}

Raising to the power 1/i we get:
**i ^{(1/i)} = e^{(Pi/2 +/- 2k Pi)}**

There is an infinity of answers and they are all real (Who said the god of mathematicians did not have a sense of humour?).

The first one, e

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